Acme Automotive Parts (AAP) Chemical Hazard Calculations (Coursework Sample)

Acme Automotive Parts (AAP) Chemical Hazard Calculations Author’s Name: Institution: Course: Date: Acme Automotive Parts (AAP) Chemical Hazard Calculations Part One Calculating the exposure concentration in mg/m3 for the aerosols Calculating exposure concentration in mg/m3 for the aerosols requires one to use the following formula; where C stands for air concentration in mg/m3, M is the actual mass of the substance in mg, and V is the air volume. On the other hand, 1 ug to mg = 0.001 mg. 1 Manganese fumes Lab results = 5ug Volume = 30L C = 0.005 * 1000 /30L = 0.167 mg/m3 2 Copper Fumes Lab results = 140ug Volume = 960L C = 0.14 * 1000 /960L = 0.146 mg/m3 3 Lead fumes Lab results = 40ug Volume = 960L C = 0.04 * 1000 /960L = 0.042 mg/m3 Calculating the exposure of vapours per million (ppm) Calculating exposure concentration, the exposure of vapors per million (ppm) requires one to use the following formula; where the Cv is air concentration and the MW is the molecular weight, grams/mole. 1 1,2,4 Trimethylbenzene Lab results = 5ug Volume = 48L Concentration = 0.005 *1000 / 48 L = 0.104 mg/m3 ppm = 0.104 (24.45 L) / 120.19 = 0.0211 ppm 2 Toluene Lab results = 125ug Volume = 48L Concentration = 0.125 *1000 / 48 L = 2.6 mg/m3 ppm = 2.6 (24.45 L) / 92.14 = 0.69 ppm 3 Xylene Lab results = 20ug Volume = 48L Concentration = 0.02 *1000 / 48 L = 0.417 mg/m3 ppm = 0.417 (24.45 L) / 106.16 = 0.096 ppm 4 Metal Working Fluids Lab results = 500ug Volume = 720L Concentration = 0.5* 1000 / 720 L = 0.694 mg/m3 ppm = 0.694 (24.45 L) / 470 = 0.036 ppm Comparing the calculated exposures to the occupational exposure limits (OELs) Manganese fume slightly exceeds the stipulated 0.1 mg/m3 occupational exposure limits (OELs) of the ACGIH 8-hour TWA by 0.067 mg/m3. Also, the copper fumes go slightly higher than the 0.1 mg/m3 stipulated by the OSHA 8-hour TWA by 0.046 mg/m3 (Park, 2012). I chose to use OSHA and the ACGIH occupational exposure limits since they are among those that are highly recognized globally. I think the risk associated with each exposure is not acceptable since, even if it is small, it has a higher chance of adversely affecting the employees. Part Two This part will convert the results from the noise sampling derived from the ACME Facility survey from the dBA to the percentage form. The formula for converting the results that have been collected from the 8-Hour Shifts will be TWA = (16.61[log(10) (Dose/100)]) + 90, while that for longer than 8-Hour Shifts will be Dose = Shift length / T ( T = 2 [(L-90) / 5]) (OSHA, 2019b). 1. Shipping/Receiving area: 8 hours shift: TWA = (16.61[log(10) (Dose/100)]) + 90 78.3 – 90 = 16.61 [log (10) (Dose/100)] + (90 – 90)-11.7 / 16.61 = log (10) (Dose/100) -0.704 = log (10) (Dose/100) Dose = antilog (-0.704) (100) = 0.19796 *100 = 19.8 % 2. Hydraulic Pressing area: Longer than 8 hours: T = 2 [(L-90) / 5] Dose = 8 / 2 [(93-90) / 5] Dose = 8 / 2 0.6 = 8 / 0.36 = 22.22 12-Hour Shift = 12 / 22.22 x 100 = 54 % 4 Metalworks area: Longer than 8 hours: T = 2 [(L-90) / 5] Dose = 8 / 2 [(84-90) / 5] Dose = 8 / 2 [-1.2] = 8 / 0.435 = 18.4 12-Hour Shift = 12 / 18.4 x 100 = 65 % 5 Robotic-welding area: Longer than 8 hours: T = 2 [(L-90) / 5] Dose = 8 / 2 [(80.5-90) / 5] Dose = 8 / 2 [-1.9] = 8 / 0.268 = 29.85 12-Hour Shift = 12 / 29.85 x 100 = 40 % 6 Hand-welding area; Longer than 8 hours: T = 2 [(L-90) / 5] Dose = 8 / 2 [(81.3-90) / 5] Dose = 8 / 2 [-1.74] = 8 / 0.299 = 26.76 12-Hour Shift = 12 / 26.76 x 100 = 45 % 7 Paint Booths area: Longer than 8 hours: T = 2 [(L-90) / 5] Dose = 8 / 2 [(79.5-90)...