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2 pages/≈550 words

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MLA

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Mathematics & Economics

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Lab Report

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English (U.S.)

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# Industrial Calculations: Determination Of Hygiene At The Industry (Lab Report Sample)

Instructions:

Determination of hygiene at the industry

source..Content:

Student’s Name
Instructor’s Name
Subject
DD MM YYYY
Question 8

Question 9
P

ppm | Grams | Air volume (I) | Mol. Wt. |

24.45 | 0.02542 | 75 | 339 |

2 | 0.00228 | 300 | 93 |

1000 | 7.164 | 1200 | 146 |

0.002 | 0.000055 | 2650 | 254 |

_{1}V_{1}/T_{1}= P_{2}V_{2}/T_{2}T_{1}= T_{2}P_{1}V_{1}= P_{2}V_{2}V_{2}= P_{1}V_{1}/P_{2}V_{2}= 2200*1.55/14.70 = 231.97 ft^{3}Solution: The gas will occupy 231.97 square feet if the typical A1 hydrogen gas cylinder has 1.55 cubic feet of gas that is compressed at 2,200 pounds per square inch at the same temperature and normal atmospheric pressure. Question 10 15°F = 263.7 K 25°C = 298.2 K V_{1}/T_{1}= V_{2}/T_{2}V_{2}= T_{2}V_{1}/T_{1}V_{2}= 298.2*15/263.7 = 16.96 liters Solution: The new air volume will be 16.96 liters if a 15-liter air sampling bag is filled at 15°F ambient temperature and reverted to 25°C under constant pressure. Question 11 32°F = 273 K P_{1}V_{1}/T_{1}= P_{1}2V_{1}/T_{2}1/T_{1}= 2/T_{2}T_{2}= 2T_{1}T_{2}= 546 K Solution: The temperature must be 546 K in order to double the 1 cubic meter volume that is occupied by a gas at a temperature of 32°F. Question 12 P_{1}V_{1}= P_{2}V_{2}P_{2}= 1.05P_{1}P_{1}V_{1}= 1.05P_{1}V_{2}V_{1}= 1.05V_{2}V_{2}= V_{1}/1.05 V_{2}= 1/1.05 = 0.95 m^{3}Solution: At this point, a gas that occupies 1 cubic meter at a pressure of 1 atmosphere will occupy 0.95 liters with an increase of 5% in atmospheric pressure. Question 13 110°F = 316....Get the Whole Paper!

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