# Solving Sample Equations On Algebra And Expounding On Properties Of Real Numbers (Math Problem Sample)

solving sample equations on algebra and expounding on properties of real numbers

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Algebra

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Algebra

1 2a (a – 5) + 4 (a – 5)

= 2a (a) – 2a (5) + 4 (a) – 4 (5) Using the distributive property, multiply the terms

within the parentheses with term outside, to remove

parentheses.

= 2a2 -10a + 4a – 20 Add the like terms (coefficients of a) together, and simplify [commutative property]

= 2a2 – 6a – 20 Combine like terms

2 2w – 3 + 3(w – 4) – 5(w – 6)

= 2w – 3 + 3(w) + 3(-4) – 5 (w) – 5(-6) Using the distributive property, multiply the

terms within the parentheses with term

outside, to remove the parentheses.

= 2w – 3 + 3w – 12 – 5w + 30

= 2w + 3w – 5w – 3 – 12 + 30 Group like terms together (coefficients of w)

= 0 + 15 simplify.

= 15 (Answer).

3 0.05(0.3m + 35n) – 0.8(-0.09n – 22m)

= 0.05 (0.3m) + 0.05 (35n) – 0.8 (-0.09n) – 0.8 (-22m) Distribution of the

multiplication by

0.05 and 0.8

= 0.015m + 1.75n + 0.072n + 17.6m

= 0.015m + 17.6m + 1.75n + 0.072n Group the like terms, both coefficients

m and n.

= 17.615m + 1.822n Combine like terms

Properties of Real Numbers

Properties of real number have been very effective and fundamental in solving algebraic equations. The properties mainly encompass; closure property, which depicts that the sum and multiplication of real numbers is equivalent to real numbers, and associative property, which is tho

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