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APA
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Mathematics & Economics
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Math Problem
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Homework on graphs, slopes and functions (Math Problem Sample)

Instructions:

please complete the following task: Homework on graphs, slopes and functions
You are to complete Questions 288, 300, 308, 350, 358, 370, 380, 386, 392, 402, 406, 408, 410, 418, 424, 446, 464, 476 in attached pics.

source..
Content:

288.
a=2, b=-5
x/a + y/b = 1
x/2 + y/-5 = 1
(-5x+2y)/-10 = 1
-5x+2y=-10
5x-2y=10
2y=5x-10
m= 5/2, b= -5
300.
6x+4y=12
4y=-6x+12
y= -6x/4 + 12/4
y= -(3/2)x + 3
m= -3/2 , b=3
308.
y= -x+2
If y=0 then x=2
If x=0 then y=2
Therefore, pts. are (2,0) & (0,2)
350.
4x+2y=6
2y=-4x+6
y= -4/2 x +6/2
y= -2x + 3
m1=-2
6x+3y=3
3y=-6x+3
y=-2x+1
m2=-2
Therefore: parallel (//)
358.
y=-4, y=3
Y=mx+b
y= (0)x-4
.:m=0
y= (0)x+3
.:m=0
Therefore: parallel (//)
370.
3x-2y=82x+3y=6
-2y=-3x+83y=-2x+6
Y= (3/2)x+8y= -(2/3)+2
Y=(3/2)x-4m2= -(2/3)
m1=3/2
m2= 1/ (-m1)
-(2/3) = 1/ (-3/2)
-(2/3) = -2/3
Therefore: perpendicular
380.
6x-4y=58x+12y=3
-4y=-6x+512y=-8x+3
Y= (3/2)x - (5/4)y=-(2/3)x+ 1/4
m1= 3/2m2=-2/3
m2= 1/ (-m1)
-(2/3) = 1/ (-3/2)
-(2/3) = -2/3
Therefore: perpendicular
386.
Slope=3 , y-int (0,5)
M=3, b=5
Y=mx+b
Y=3x+5
392.
Slope= -2, y-int (0,-3)
M=-2, b=-3
Y=mx+b
Y=-2x-3
402.
(1,-2), (0,-5)
y-y1 = ((y2-y1)/ (x2-x1)) (x-x1)
Y+2 = ((-5+2)/ (0-1)) (x-1)
Y+2 = ((-3)/ (-1)) (x-1)
Y+2=3(x-1)
Y+2=3x-3
Y=3x-5
406.
(3,-1), (0,3)
y-y1 = ((y2-y1)/ (x2-x1)) (x-x1)
Y+1 = ((3+1)/ (0-3)) (x-3)
Y+1 = ((3)/ (-3)) (x-3)
Y+1 = (-1) (x-3)
Y+1 = -x+3
Y=-x+2
408.
(0,-2), (2,-2)
y-y1 = ((y2-y1)/ (x2-x1)) (x-x1)
Y+2 = ((-2+2)/ (2-0)) (x-0)
Y+2 = 0
Y=-2
410.
M= 5/8 , (8.3)
Y-y1=m(x-x1)
Y-3= (5/8)(x-8)
Y-3= (5/8)x-5
Y= (5/8)x-5+3
Y= (5/8)x-2
418.
Horizontal line c

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