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# Math Problem (Precalc group 5) (Math Problem Sample)

Instructions:

9.1 (a) Solve each system by substitution. 3x + 4y = 4 x - y = 13 (b) Use the given row transformation to change each matrix as indicated. {1 -4}; -7 time row 1 added to row 2 {7 0} 9.3 (a) Find the Values of each determinant {6 -4} {0 -1} (b) Give all solutions of each nonlinear system of equations, including those with nonreal complex components. x^2 + y = 2 x – y = 0

source..Content:

Precalc group 5

Name

Course

Instructor

Date

9.1 (a) Solve each system by substitution

3x + 4y = 4x - y = 13

Calculations

X-Y=13

x=13+y

3x+4y=4

3(13+y) +44=4

39+3y+4y=4

7y=-35

Y=35/7=5

X=13-5=8

X=8, Y=-5(b) Use the given row transformation to change each matrix as indicated.{1 -4}; -7 time row 1 added to row 2{7 0}=7*(1+-4)+ {7 0)={14 -28}=7{2 -4}9.3 (a) Find the Values of each determinant {6 -4}{0 -1}Determinant= ad-bc=(6*-1)-(4*0)= -6(b) Give all solutions of each nonlinear system of equations, including those with nonreal complex components.x^2 + y = 2x – y = 0

Calculation

X^2+y=2

Name

Course

Instructor

Date

9.1 (a) Solve each system by substitution

3x + 4y = 4x - y = 13

Calculations

X-Y=13

x=13+y

3x+4y=4

3(13+y) +44=4

39+3y+4y=4

7y=-35

Y=35/7=5

X=13-5=8

X=8, Y=-5(b) Use the given row transformation to change each matrix as indicated.{1 -4}; -7 time row 1 added to row 2{7 0}=7*(1+-4)+ {7 0)={14 -28}=7{2 -4}9.3 (a) Find the Values of each determinant {6 -4}{0 -1}Determinant= ad-bc=(6*-1)-(4*0)= -6(b) Give all solutions of each nonlinear system of equations, including those with nonreal complex components.x^2 + y = 2x – y = 0

Calculation

X^2+y=2

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