Electrostatics Assignment (Math Problem Sample)
THIS WAS Q&A PHYSICS ASSIGNMENT WITH DIFFERENT PARTS. SOME SAMPLES OF THE QUESTIONS ARE AS SHOWN BELOW
.KNOWLEDGE CHECK ON THE TOPIC
13 a. Draw an electric field for each of the particles following basic field drawing principles.
14. For each example below, show the direction of the magnetic field at each of the designated points (*). If needed, you can use x dot into the page and a dot for out of the page. Where possible, your vectors should also demonstrate appropriate field strength.
COMMUNICATE REASONING
16. An experiment is done where a glass rod is brought near to colored sequins (conductive metallic disks) The sequins are lifted up by the glass rod. Three students discuss what this means:
Student 1: This must mean that the glass rod is positively charged and the sequins are negatively charged
Student 2: Actually, we don’t know their charge, just that they are different. It is possible that the glass rod is negative and the sequins positive.
Student 3: I think you are both wrong. The sequins could be neutrally charged. All we know is that the rod is charged.
Use excellent knowledge on charges to settle the argument. Tell us which student is correct (if any) and justify your answer using the CER model (make a Claim, cite the Evidence, give Reasoning)
Electrostatics Assignment
Student’s Name
Institutional Affiliation
Course Name
Lecturer’s Name
Electrostatics Assignment
KNOWLEDGE CHECK ON THE TOPIC
13 a. Draw an electric field for each of the particles following basic field drawing principles.
14. For each example below, show the direction of the magnetic field at each of the designated points (*). If needed, you can use x dot into the page and a dot for out of the page. Where possible, your vectors should also demonstrate appropriate field strength.
15. An alpha particle (charge = 3.2*10^-19 C) is passing through parallel plates shown below
* In the image above, draw the electric field between the plate
The electric field between the plates is directed from the positive plate to the negative plate.
* The electric field strengths is 3*10^6 N/C. Find the magnitude of the force on the alpha particle.
The magnitude of the force on the alpha particle is given by F=qE, where q is the charge of the alpha particle and E is the strength of the electric field. Substituting in the given values, we find that
F = (3.2×10−19 C) (3×10^6 N/C)
=9.6×106−13 N.
* A magnetic field is created in the area between the plates such that the alpha particle now travels in a straight line. What direction does the magnetic force need to be?
The magnetic force needs to be in the opposite direction of the electric force in order to cancel it out and allow the alpha particle to travel in a straight line.
* To achieve the magnetic force determined in (c), what direction must the magnetic field be in?
The magnetic field must be in the same direction as the electric field in order to produce the magnetic force in the opposite direction. The alpha particle will travel in a straight line because the electric force and the magnetic force cancel each other out.
COMMUNICATE REASONING
16. An experiment is done where a glass rod is brought near to colored sequins (conductive metallic disks) The sequins are lifted up by the glass rod. Three students discuss what this means:
Student 1: This must mean that the glass rod is positively charged and the sequins are negatively charged
Student 2: Actually, we don’t know their charge, just that they are different. It is possible that the glass rod is negative and the sequins positive.
Student 3: I think you are both wrong. The sequins could be neutrally charged. All we know is that the rod is charged.
Use excellent knowledge on charges to settle the argument. Tell us which student is correct (if any) and justify your answer using the CER model (make a Claim, cite the Evidence, give Reasoning)
ANSWER
Claim:
Student 1 is correct. The glass rod is positively charged and the sequins are negatively charged.
Evidence:
* Opposite charges attract, while like charges repel. When the glass rod is brought near the sequins, the sequins are attracted to the rod. This means that the sequins must have a negative charge, since opposite charges attract.
* Glass is a dielectric material, which means that it does not conduct electricity well. When the glass rod is rubbed with a cloth, it becomes positively charged. This is because electrons are transferred from the cloth to the rod. The sequins, being a conductor, are able to take on the negative charge that was left on the cloth.
Reasoning:
