# Solving and Interpreting Independent and Dependent T-test Problems (Math Problem Sample)

The task was about solving and interpreting independent and dependent t-test problems. A worksheet with the problems had been provided. My task was to demonstrate the solution to each scenario by showing how to work through each example in detail. Also, I was supposed to to explain all of the steps in my own words.

source..Deliverable 05 – Worksheet

Independent samples:One of our researchers wishes to determine whether people with high blood pressure can reduce their systolic blood pressure by taking a new drug we have developed. The sample data is shown below, where x1 represents the mean blood pressure of the treatment group and x2 represents the mean for the control group. Use a significance level of 0.01 and the critical value method to test the claim that the drug reduces blood pressure. We do not know the values of the population standard deviations.

### Other Topics:

- Understanding the Law of Sines and CosinesDescription: 1 Type out the two equations substituting the numbers from the diagram.DemonstrationDrawing out the triangle first: 10096502971800A c= 30 b=15 B a Cangle ABC=20° (β)angle ACB=Ɣangle BAC=α ( This is the angle in question) Solution Equation 1 (obtained from the law of cosines) b2=a2+c2-2ac...1 page/≈275 words| No Sources | Other | Mathematics & Economics | Math Problem |
- Examples of Logical ProblemsDescription: 1 ∀x(Ax → Bx) 2 ∀x (Ax→Cx) 3 Ad→Bd 1, ∀Elim 4 Ad→Cd 2, ∀Elim 5 Ad Assumption for CP 6 Bd 3,5 →Elim 7 Cd 3,4 → Elim 8 Bd & Cd 6,7 & Intro 9 Ad → (Bd &Cd) 5,-8 →Intro 10 ∀x[Ax→(Bx&Cx)] 9, ∀Intro 1 ∀x(¬Cx →¬Ax) 2 ∃xCx → (∃x¬(¬Bx V ¬ Dx) 3 ¬(¬∃xAx V ∃xBx) Assumption for IP 4 ¬Cd → ¬Ad 1, ∀ Elim 5 ...6 pages/≈1650 words| No Sources | Other | Mathematics & Economics | Math Problem |
- Solving Mathematical Equation Involving IntegrationDescription: To evaluate ʃ x sin 3x dx, we use the method of integration by parts given by the formula; ʃ u dv = uv-ʃ v du Let u = x, dv = sin 3x; then, v= -cos 3x and du = dx. Now substituting in the formula we get; ʃ x sin 3x dx = x-1/3cos 3x-ʃ-1/3cos 3x dx = -1/3cos 3x+1/9sin 3x+C, where C is a constant. ...2 pages/≈550 words| No Sources | Other | Mathematics & Economics | Math Problem |