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# management (Research Paper Sample)

Instructions:
1. Suppose that the specification for a part (in inches) are 6.00 ± 0.02, and the Taguchi loss function for some part is estimated to be L(x) = 6,800 (x - T)2. Determine the loss if x = 6.05 inches. The Taguchi Loss Function is: L(x) = k(x - T)2 The Excel template Taguchi can be used to compute the loss per part; use the second portion of the template “Loss Calculation for a Specific x” L(x) = k(x - T)2 k=6,800, x=6.05, T=6 L(x) = 6,800 * (6.05 - 6)2 L(x) = 6,800 * 0.052 L(x) = 6,800 * 0.0025 L(x) = \$17 The loss associated with x = 6.05 is equals to \$17 source..
Content:
Student Name Course Code Course Name Learning Institution Lecturer Complete the questions below. For problems, please show all work. For questions, please use complete sentences and proper grammar. Due Saturday 11PM 1 Suppose that the specification for a part (in inches) are 6.00 ± 0.02, and the Taguchi loss function for some part is estimated to be L(x) = 6,800 (x - T)2. Determine the loss if x = 6.05 inches. The Taguchi Loss Function is: L(x) = k(x - T)2 The Excel template Taguchi can be used to compute the loss per part; use the second portion of the template “Loss Calculation for a Specific x” L(x) = k(x - T)2 k=6,800, x=6.05, T=6 L(x) = 6,800 * (6.05 - 6)2 L(x) = 6,800 * 0.052 L(x) = 6,800 * 0.0025 L(x) = \$17 The loss associated with x = 6.05 is equals to \$17 2 A quality characteristic has a design specification (in cm.) of 0.200 ± 0.02. If the actual process value of the quality characteristic is at the boundary of the tolerance on either side, the product will require a repair of \$30. Find the value of k and state the Taguchi loss function. What is the loss associated with x = 0.205? The Taguchi Loss Function is: L(x) = k(x - T)2 The Excel template Taguchi can be used to compute this. K=L(x)/(x-T)2 L(x)= \$30, (x-T)=0.02 K= 30 / (0.02)2 K= 30 / 0.0004 K = 75,000 Taguchi Loss Function is L(x)=75,000(x-T)2 L(x) = k(x - T)2 k= 75,000, x=0.205, T=0.200 L(x)=75,000 * (0.205 – 0.200)2 L(x) = 75,000 * 0.0052 L(x) = 75,000 * 0.000025 L(x) = \$1.875 The loss associated with x = 0.205 is equals to \$1.875 3 The service center for a brokerage company provides three functions to callers: account status, order confirmations, and stock quotes. The reliability was measured for each of these services over 1 month with these results: 0.80, 0.70, and 0.96, respectively. What is the overall reliability of the call center? The overall reliability of the call center is 0.5376 ; obtained through the series system reliability calculation as shown below; Overall Reliability = (R1* R2 * R3 ) = 0.80 * 0.70 * 0.96 = 0.5376 4. Marine International manufactures an aquarium pump and is trying to decide whether to produce the filter system in-house or sign an outsourcing contract with Bayfront Manufacturing to make the filter system. Marine’s expertise is producing the pumps themselves but they are considering producing the filter systems also. To establish a filter system production area at Marine International, the fixed costs is \$300,000 per year and they estimate their variable cost of production in-house at \$12.25 per filter system. If Marine outsources the production of the filter system to Bayfront, Bayfront will charge Marine \$30 per filter system. Should Marine International outsource the production of the filter system to Bayfront if marine sells 25,000 pumps a year? You can use the Excel Break-Even spreadsheet template to solve this. Fixed Cost (FC)=\$300,000 Variable Cost (VC)= \$12.25 @unit Pumps sold (units sold) = 25,000 Total In-house Production Cost = FC + (VC*units) = \$300,000 + (\$12.25 * 25,000) =\$300,000 + \$306,250 Total In-house Production Cost = \$606,250 Total Outsourced Cost = Outsourcing cost * pumps sold = \$30 * 25,000 Total Outsourced Cost =\$750,000 Cost difference (In-House - Outsourced) = \$606,250 - \$750,000 =-\$143,750 As an optimal decision, Marine International should not outsource the produ...
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