Math/Physic/Economic/Statistic Problems (Essay Sample)

EDU9615 Problem Set 2 Student’s Name Institutional Affiliation Course Name Instructor’s Name Submission Date EDU9615 Problem Set 2 Chapter 10: Set 2 (14, 18 and 19) 14. (a) 3609975380365The table was screenshotted straight from the SPSS output. It was then resized.00The table was screenshotted straight from the SPSS output. It was then resized. Since value p < 0.01; reject null hypothesis (Ho) The samples does come from identical populations. Effect size is 96/99 = .9697 (b) 3933825323850The table was screenshotted straight from the SPSS output. It was then resized.00The table was screenshotted straight from the SPSS output. It was then resized. Since value p < 0.01; reject null hypothesis (Ho)   The samples do not come from identical populations. Effect size is 72/75 = .96 18. (a). We use the table of Approximate Power for Studies with a significance level of 0.05 to determine the power for a study with =4, with each group size n=50 and small effect size. The tabular value for power is 0.19. (b). We use the table of Approximate Power for Studies with a significance level of 0.05 to determine the power for a study with =4, with each group size n=50, and medium effect size. The tabular value for power is 0.85. (c). We use the table of Approximate Power for Studies with a significance level of 0.05 to determine the power for the study with =4, with each group size n=50 and large effect size. The tabular value for power is 1. (d). We use the table of Approximate Power for Studies with a significance level of 0.05 to determine the power for a study with =50, with every group size n=50, and medium effect size. The tabular value for power is 0.90. Therefore, Predicted Effect Sizes Number of Group Participants in Each Group Total (a) Small 4 50 0.19 (b) Medium 4 50 0.85 (c) Large 4 50 1 (d) Medium 5 50 0.90 19. The test used here is ANOVA, and the purpose is to determine if the means are all equal or if at least one of them is different from the others. The ANOVA test uses the F-statistic, which compares the between group variance against the within group variance. The sum of freedom degrees for the F-statistic denominator is equal to sum of observations in all groups combined, minus the number of groups. For the tests shown in the table above, the two values are: dfN =k - 1 = 4 - 1 = 3 dfD = N - k = 60 - 4 = 56 For the first test, "Conformity," the test statistics can be reported as 4.21, and the p value is indicated as being less than .01. This signifies that null hypothesis could be rejected in any alpha value greater than 0.01 and that at least one of the means ...