# Solving Mathematical Problems Involving Graphing and Slopes (Math Problem Sample)

Showing the solutions to math problems.

Use the two points from the graph which are (1, 4 1/2) and (2, 9).

(1, 9/2) and (2, 9)

m = (y_2-y_1)/(x_2-x_1 )

= (9-9/2)/(2-1)

m = 9/2

The slope of the line is 9/2 .

m = (y_2-y_1)/(x_2-x_1 ) = (-4-(-5))/(3-0) = 1/3

The slope of the line is 1/3.

Student’s Name

Professor’s Name

Course Number

Date

Module 4 Test Answers:

1.

* y = 5.5x

x

0

1

1 12

2

y

0

5.5 or 5 12

8 14

11

Graph:

y

x

* The slope of the graph is positive.

1

Hours Worked

Amount Earned

2

$19.5

3

$29.25

4

$39

2 Use the two points from the graph which are (1, 4 12) and (2, 9).

(1, 92) and (2, 9)

m = y2-y1x2-x1

= 9-922-1

m = 92

The slope of the line is 92 .

3 m = y2-y1x2-x1 = -4-(-5)3-0 = 13

The slope of the line is 13.

5.

-57086590233500

-3830320278130Positive00Positive

-180149545720Zero00Zero

-1801495306705Negative00Negative-3830320240030Undefined00Undefined

6. Use the two points from the graph which are (1, 1) and (2, 3).

m = y2-y1x2-x1 = 3-12-1 = 2

m = 2

Use the point (1, 1) and m = 2 to solve for the y-intercept(b).

y = mx + b

1 = (2)(1) + b

b = -1

Therefore, the equation of the line is y = 2x – 1 or –2x + y = -1.

7. y = 13x + 2

x – intercept = -6

y – intercept = 2

8. y = 3x + 12

X

-1

-2

-3

-4

y

9

6

3

0

9. The has y-intercept(b) = -2 and point (2, 0).

So, y = mx + b

0 = m(2) – 2

0 = 2m – 2

m = 1

Therefore, the equation of the line is y = x – 2.

10. The equation y = 2.5x + 15 has a slope of 2.5 and y – intercept of 15.

11. Choose two points from the table which are (0, 3) and (1, 7) to the equation of the line.

m = y2-y1x2-x1 = 7-31-0 = 4

m = 4

The point (0, 3) has a y-intercept(b) = 3.

Therefore, the equation of the line is y = 4x + 3.

12. m = riserun = -34

Therefore, the slope of the line is -34.

13. The given two points are (-8, 4) and (-8, 10).

m = y2-y1x2-x1 = 10-40-8-(-8) = 60

There

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