Solving Mathematical Problems Involving Graphing and Slopes (Math Problem Sample)

Student’s Name
Professor’s Name
Course Number
Date
Module 4 Test Answers:
1.
* y = 5.5x
x

0

1

1 12

2

y

0

5.5 or 5 12

8 14

11

Graph:
y
x
* The slope of the graph is positive.
1
Hours Worked

Amount Earned

2

$19.5

3

$29.25

4

$39

2 Use the two points from the graph which are (1, 4 12) and (2, 9).
(1, 92) and (2, 9)
m = y2-y1x2-x1
= 9-922-1
m = 92
The slope of the line is 92 .
3 m = y2-y1x2-x1 = -4-(-5)3-0 = 13
The slope of the line is 13.
5.
-57086590233500
-3830320278130Positive00Positive
-180149545720Zero00Zero
-1801495306705Negative00Negative-3830320240030Undefined00Undefined
6. Use the two points from the graph which are (1, 1) and (2, 3).
m = y2-y1x2-x1 = 3-12-1 = 2
m = 2
Use the point (1, 1) and m = 2 to solve for the y-intercept(b).
y = mx + b
1 = (2)(1) + b
b = -1
Therefore, the equation of the line is y = 2x – 1 or –2x + y = -1.
7. y = 13x + 2
x – intercept = -6
y – intercept = 2
8. y = 3x + 12
X

-1

-2

-3

-4

y

9

6

3

0

9. The has y-intercept(b) = -2 and point (2, 0).
So, y = mx + b
0 = m(2) – 2
0 = 2m – 2
m = 1
Therefore, the equation of the line is y = x – 2.
10. The equation y = 2.5x + 15 has a slope of 2.5 and y – intercept of 15.
11. Choose two points from the table which are (0, 3) and (1, 7) to the equation of the line.
m = y2-y1x2-x1 = 7-31-0 = 4
m = 4
The point (0, 3) has a y-intercept(b) = 3.
Therefore, the equation of the line is y = 4x + 3.
12. m = riserun = -34
Therefore, the slope of the line is -34.
13. The given two points are (-8, 4) and (-8, 10).
m = y2-y1x2-x1 = 10-40-8-(-8) = 60
There