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# Mathematics Solving The Waveform In The Figure (Math Problem Sample)

Instructions:

solving

source..Content:

Solutions.

To determine the equation for the waveform in the figure. The point at which the sine is turned is on φ . The answer is in 3 parts.

Part 1

The gradient for line y= 0 is 0 therefore,

0φdθ= φ

Part 2

πφSinθ dθ=-cosθ+cosφ=1+cosφ

Part 3

π2πdθ=π

Hence, the equation of the area of the covered by the curve

φ+(1+cosφ)+ π

#2 Determine the equation for the waveform in the figure. This is a symmetric triangle wave. The equation has two parts. Each segment is of the form y=mx+b. The second segment has a negative slope and a y intercept of 2Ip.

y=mx+c

is the equation of a straight line where m=gradient and c= y-intercept?

M1=2ITP

And hence

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