Essay Available:

You are here: Home → Statistics Project → Accounting, Finance, SPSS

Pages:

1 page/≈275 words

Sources:

Level:

Other

Subject:

Accounting, Finance, SPSS

Type:

Statistics Project

Language:

English (U.S.)

Document:

MS Word

Date:

Total cost:

$ 4.68

Topic:

# Statistics: Critical Values (Statistics Project Sample)

Instructions:

The sample involves computation of the critical values and probabilities.

source..Content:

QUESTION 1

Mean,u=16.28

Standard deviation,Ïƒ=0.4

P(x<16) is given by

Wecompute the Z-value for the probability

For x=16, z= (16-16.28)/0.4=-0.7

P (z<-0.7) =

From the standard normal curve tables, we take the area to the left of 0.5 from the region z=0 to the region z=0.7.

P (z<-0.7) =0.5-P (00.7)

=0.5-0.2580=0.242

The probability that the average amount is between 16.20 and 16.30

P (16.2016.30)

We compute the Z-value for the 2 figures.

For x=16.20, Z= (16.20-16.28)/0.4=-0.2

For x=16.30, Z= (16.30-16.28)/0.4=0.05

P (-0.20.05)

From the standard normal table, we compute the area to the left side from z=-0.2 up to Z=0.This will be equal to Z=0 to Z=0.2

=P (-0.20.05) =0.0793+

The probability that the average amount is greater than 16.50 will computed as follows

We compute the Z-value of P(x>16.50)

Z-value= (16.50-16.28)/0.4=0.55

P (Z>0.55)

From the standard normal tables, we need to take the whole right side(0.5) and less the area from Z=0 to Z=0.55

P (Z>0.55) =0.5-0.2088=0.2912

The probability that the average amount is between 16.20 and 16.26

P (16.20

We need to compute the z-value for the above probability

For x=16.20, Z-value= (16.20-16.28)/0.4=-0.2

For x=16.26, Z-value = (16.26-16.28)/0.4=-0.05

P (-0.05

= -P (-0.2) +P (-0.05)

=- [1-P (Z<-0.2)] + [1-P (Z>-o.o5)]

=- [1-0.0793] + [1-0.0199]

= -0.9207+0.9801

=0.0594

99.9% of the time, the amount in the boxes will be 0.999*16.28=16.26 ounces

QUESTION 2

When it comes to apportioning students, you can either be a male or a female.So,the probabilityof student of any given gender being selected is 50%. The number of female students is 60 %( 0.6) while the number of male students is 40 %( 0.4)

Female, Q=0.6

Male, P=0.4

Students(male/female)

1/2

1/2

Number

0.6

0.4

The expected value,mean=1/2*6/10 +1/2*4/10

=0.3+0.2=0.5

The standard deviation for the random variable p is given by calculating the variance and then getting the square root.

Variance=X2ip-u2

=0.62*0.5 +0.42*0.5 -0.52

=0.18+0.08-0.25=0.01

Standard deviation=0.1

The probability that less than 58.5% of the students in the sample are female,P(á¿¤<0.585)

We compute the Z-value for the above probability.

Z-value= (0.585-0.5)/0.1

=0.085/0.1=0.85

P (á¿¤<0.85) =

From the standard normal table, we can easily get the above probability

P (á¿¤<0.85) =0.3023

The probability that more than 65% of the students are female is

P (á¿¤>0.65) =

We compute the Z-value of the probability that, more than 65% of the students are female.

Z-value= (0.65-0.5)/0.1=1.5

P (Z>1.5)

We can obtain the value for the above probability from the normal tables.

P (Z>1.5) =0.4332

The probability that the percentage of between 56% and 64% are female.

P (0.56<á¿¤<0.64).

The z-values are

For x=0.56, Z-value= (0.56-0.5)/0.1=0.6

Therefore, P (Z<0.6) =0.2257

For x=0.64, Z-value= (0.64-0.50)/0.1=1.4

Therefore,P (Z<1.4) =0.4192

The probability that the percentage of the students in the sample are female is =0.4192-0.2257=0.1935

The table below is the normal table used in solving question 1. The "0.1"s are running down, while the "0.01"s arerunning along.

Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09

0.0 0.0000 0.0040 0.0080 0.0120 0.0160 0.0199 0.0239 0.0279 0.0319 0.0359

0.1 0.0398 0.0438 0.0478 0.0517 0.0557 0.0596 0.0636 0.0675 0.0714 0.0753

0.2 0.0793 0.0832 0.0871 0.0910 0.0948 0.0987 0.1026 0.1064 0.1103 0.1141

0.3 0.1179 0.1217 0.1255 0.1293 0.1331 0.1368 0.1406 0.1443 0.1480 0.1517

0.4 0.1554 0.1591 0.1628 0.1664 0.1700 0.1736 0.1772 0.1808 0.1844 0.1879

0.5 0.1915 0.195...

Get the Whole Paper!

Not exactly what you need?

Do you need a custom essay? Order right now:

### Other Topics:

- Elaborate Concepts On The T-test Using Calculations And SpssDescription: A t-test was conducted to test whether there was a significant difference between the baselines and post LDL measurements of 15 participants after a nurse-based intervention...3 pages/≈825 words| No Sources | Other | Accounting, Finance, SPSS | Statistics Project |
- One Sample T-TestDescription: The expenditure variable chosen was the Annual Household Income variable named as "SE-Income." A one-sample t-test was used to investigate whether annual household income data has a mean equal to $9,500 (hypothesized mean). The test was conducted using SPSS, s statistical software used mainly for social ...2 pages/≈550 words| No Sources | Other | Accounting, Finance, SPSS | Statistics Project |
- Current Analysis Evaluated Three Companies: BASF, Solvay, and EvonicDescription: According to TCFD, a firm should be in a position to make its discloser with regards to climate change on aspects of strategy, governance, risk, and targets. This is from a resolution that climate change has serious consequences on financial stability of a firm. Besides affecting a lot of sectors, it has...7 pages/≈1925 words| No Sources | Other | Accounting, Finance, SPSS | Statistics Project |