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2 pages/≈550 words
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APA
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Engineering
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English (U.S.)
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Topic:

Answer Power Electronic Questions Research Assignment (Term Paper Sample)

Instructions:

ANSWER POWER ELECTRONIC QUESTIONS

source..
Content:

Chapter 3 #1: Determine the equation for the waveform in the figure. The point at which the sine is turned on is φ. Hint: the answer should have 3 parts.
02540
Part 1
Since gradient is 0 for the line y=0,
0φdѲ = φ
Part 2
φπSin Ѳ dѲ= [-Cos Ѳ+Cos φ]=1+Cos φ
Part 3
π2πdѲ = π
Therefore, the equation for the area covered by the curve is
φ+ (1+Cos φ)+ π
Chapter 3 #2: Determine the equation for the waveform in the figure. This is a symmetric triangle wave. The equation has two parts. Each segment is of the form y=mx+b. The second segment has a negative slope and a y intercept of 2Ip.
0101600
Equation of a straight line is given by: y = mx + c
Where m is the gradient and c the y – intercept
For positive gradient;
M1 = 2IPT
Therefore, Y1 = 2IPTX
For negative gradient;
M2 = - 2IPT and Y intercept = 2IP
Therefore, Y2 = - 2IPTX + 2IP
Area under the triangular wave is given by;
0TY1+Y2.dt
0T2IPTX - 2IPTX + 2IP.dt
Substituting the values of y1 and y2 in the above equation and integrating by parts you get;
=2IPX0T
Chapter 3 #3:
* Calculate the equation for the average value of the partial sine wave from Figure 3-33.
Average value of the partial sine wave: from the figure, the quarter sine wave has the limits
0‹ φ ‹π
V average = 2π φπVpSin Ѳ. dѲ
Vp is the peak voltage
V averag

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