# Rheostat Resistance (Math Problem Sample)

Rheostat Resistance

A 72 Ohm Coil of wire is connected in series with an adjustable Resistor whose Resistance can be varied from 0 to 88 Ohms. if the line Potential of wire is 115 volts, what is the Rheostat resistance when Power taken by the coil is 90 watts?

From ohms law

I=V/R and P = VI

P = V(V/R) = V2R

90 = V2/72

V2 = 90 × 72 = 6480

V = 80.5 Volts

But I = V/R

I = 80.5/72

I = 1.118 Amps

The voltage through this coil is 115 volts and a current of 1.118 Amperes

Therefore, the total Resistance, R = V/I

R = 115/1.118 = 102.86 Ohms

The rheostat resistance = Total resistance – Resistance of the Coil

= 102.86 – 72

= 30.86 Ohms

Rheostat Resistance

A 72 Ohm Coil of wire is connected in series with an adjustable Resistor whose Resistance can be varied from 0 to 88 Ohms. if the line Potential of wire is 115 volts, what is the Rheostat resistance when Power taken by the coil is 90 watts?

From ohms law

I=V/R and P = VI

P = V(V/R) = V2R

90 = V2/72

V2 = 90 × 72 = 6480

V = 80.5 Volts

But I = V/R

I = 80.5/72

I = 1.118 Amps

The voltage through this coil is 115 volts and a current

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